# Depth First Search

# Bicoloring

In 1976 the "Four Color Map Theorem" was proven with the assistance of a computer. This theorem states that every map can be colored using only four colors, in such a way that no region is colored using the same color as a neighbor region.

Here you are asked to solve a simpler similar problem. You have to decide whether a given arbitrary connected graph can be bicolored. That is, if one can assign colors (from a palette of two) to the nodes in such a way that no two adjacent nodes have the same color. To simplify the problem you can assume:

- no node will have an edge to itself.
- the graph is nondirected. That is, if a node
**a**is said to be connected to a node**b**, then you must assume that**b**is connected to**a**. - the graph will be connected. That is, there will be at least one path from any node to any other node.

#### Input

Consists of several test cases. Each test case starts with a line containing the number **n** (**0** ≤ **n** ≤ **1000**) of different nodes. The second line contains the number of edges **l** (**1** ≤ **l** ≤ **250000**). After this **l** lines will follow, each containing two numbers that specify an edge between the two nodes that they represent. A node in the graph will be labeled using a number **a** (**1** ≤ **a** ≤ **n**). The last test contains **n** = **0** and is not to be processed.

#### Output

You have to decide whether the input graph can be bicolored or not, and print it as shown below.

3 3 1 2 2 3 3 1 8 12 1 2 2 4 3 4 3 1 3 7 7 6 4 6 1 6 2 5 5 6 4 8 5 8 0

NOT BICOLOURABLE. BICOLOURABLE.