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Minimum method

published at 1/11/15, 1:46:19 pm

Як у третьому випадку Sample 3 4 4 1 5 3 Ми отримуємо відповідь 3?

published at 2/13/17, 3:23:41 pm

чо 3

published at 6/3/18, 5:27:11 pm

Тесты подходят под условие? Проверьте формат вывода.

published at 1/10/19, 11:17:59 am

сталина на вас нет!

published at 3/1/23, 8:05:44 pm

Thanks for idea. Mrismayil

published at 1/9/24, 7:08:30 am

include <iostream>

using namespace std; int main() { int n; cin >> n; int arr[n]; for(int i = 0; i < n; i++){ cin >> arr[i]; } int k = arr[0], s = 0, num_i = 0; for(int i = 0; i < n; i++){ int min = i; int rem_i = num_i;

    for(int j = i + 1; j < n; j ++){
        if(arr[j] < arr[min]) min = j;
    }

    int t = arr[min];
    arr[min] = arr[i];
    arr[i] = t;

    for(int m = 0; m < n; m ++){
        if(arr[m] == k){
            num_i = m;
            break;
        }
    }

    if(rem_i != num_i) s++;

}
cout << s << endl;
return 0;

}